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The radius of a circle having minimum area which touches the curve y=4-x^2 and the line y=|x| is

Krishnendra Dwivedi , 8 Years ago
Grade 12th pass
anser 1 Answers
Arun
Centre : (0, 4-r)
Length of perpendicular from (0, 4-r) to line x-y = 0 is:
 
r = |(0 -4 +r)/\sqrt2|
r - 4 = + - \sqrt2 r
On solving
r = 4(\sqrt2 -1)
 
Regards
Arun (AskIITians forum expert)
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Last Activity: 8 Years ago
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